Factorisation of the expression $17 p^{2} q - 102 p q^{2}$ results in:

17 p q (p - 8 q)

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17 p q (p - q)

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17 p q (p - 4 q)

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17 p q (p - 6 q)

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Solution

The correct option is C $17 p q (p - 6 q)$
$17 p^{2} q - 102 p q^{2}$

$= (17 \times p \times p \times q) - (17 \times 6 \times p \times q \times q)$

$= 17 p q (p - 6 q)$

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