Factorisation of the expression $4 m^{2} + 12 m + 9$ results in:

(2 m + 3) (2 m + 3)

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(3 m + 2) (3 m + 2)

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(3 m + 2) (3 m - 2)

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(2 m + 3) (2 m - 3)

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Solution

The correct option is B $(2 m + 3) (2 m + 3)$
$4 m^{2} + 12 m + 9$

$= {(2 m)}^{2} + 2 (2 m) (3) + {(3)}^{2}$

$= {(2 m + 3)}^{2}$ ... $[∵ {(a + b)}^{2} = a^{2} + 2 a b + b^{2}]$

$= (2 m + 3) (2 m + 3)$

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$(12 m^{2} - 27) = ? (a) (2 m - 3) (3 m - 9) (b) 3 (2 m - 9) (3 m - 1) (c) 3 (2 m - 3) (2 m + 3) (d) n o n e o f t h e s e$

3 m^{2} = 2 m^{2} - 9

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