Factorisation of $- x^{2} y - x + 3 x y + 3$ gives _________ .

(x y - 1) (3 + x)

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(x + 1) (3 - x y)

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(x y + 1) (3 + x)

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(x y + 1) (3 - x)

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Solution

The correct option is D $(x y + 1) (3 - x)$
$- x^{2} y - x + 3 x y + 3$
$= - x (x y + 1) + 3 (x y + 1)$
$= (3 - x) (x y + 1)$
$= (x y + 1) (3 - x)$

$So, - x^{2} y - x + 3 x y + 3 can be factorised as (x y + 1) (3 - x) .$

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