Question

Factorisation of $-x^{2}y-x+3xy+3$ gives _________ .

• A. $(xy-1)(3+x)$
• B. $(x+1)(3-xy)$
• C. $(xy+1)(3+x)$
• D. $(xy+1)(3-x)$

Answer 1

The correct option is D $(xy+1)(3-x)$

$\text{The given expression is}-x^{2}y-x+3xy+3.$

$-x^{2}y-x+3xy+3$
$=-x(xy+1)+3(xy+1)$
$=(3-x)(xy+1)$
$=(xy+1)(3-x)$

$\text{So,}-x^{2}y-x+3xy+3\text{can be}\text{factorised as}(xy+1)(3-x).$