Factorise $1 - 100 a^{2}$ by using formula

(1 + 10 a) (1 - 10 a)

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(1 + a) (1 - 10 a)

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(1 + 10 a) (1 - a)

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(10 a) (1 - 10 a)

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Solution

The correct option is A $(1 + 10 a) (1 - 10 a)$
$F a c t o r i z i n g {1 - 100 a}^{2}, = (1 - 10 a) (1 + 10 a)$ using the identity $(a^{2} - b^{2}) = (a + b) (a - b)$

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Similar questions

A_{1}

A_{2}

\times

3 A_{1}^{T} + I^{3} = 10 A_{1}

4 I^{3} + 3 A_{2} = 7 A_{2}^{T}

a^{2} - 10 a + 25

a^{2} - 10 a + 21

a^{2} + 10 a + 24

Factorise by grouping method:

$(2 a - b)^{2} - 10 a + 5 b$

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