Factorise 1−(2x−3y)2
(1+2x−3y)(1−2x+3y)
(1+2x+3y)(1−2x+3y)
(1−2x−3y)(1−2x+3y)
(2x−3y−1)(1−2x−3y)
Given 1−(2x−3y)2 Using (a2−b2)=(a+b)(a−b) Taking a = 1 and b = 2x−3y, we have (1+2x−3y)(1−2x+3y)