Factorise:

$1 - 8 a^{3}$

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Solution

$W e k n o w a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2}) 1 - 8 a^{3} = 1^{3} - (2 a)^{3} = (1 - 2 a) (1^{2} + 2 a + (2 a)^{2}) = (1 - 2 a) (1 + 2 a + 4 a^{2})$

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