Factorise $121 x^{2} - 49 y^{2}$ .

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Solution

As we know the algebraic identity,
$a^{2} - b^{2} = (a + b) (a - b)$
So, it can be factorized by using this identity, we can write:
$121 x^{2} - 49 y^{2}$ $=$ ${(11 x)}^{2} - {(7 y)}^{2}$
$=$ $(11 x + 7 y) (11 x - 7 y)$
Therefore factors of $121 x^{2} - 49 y^{2}$ $=$ $(11 x + 7 y) (11 x - 7 y)$ .

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