Factorise $13 x^{2} + 31 x + 10$

Open in App

Solution

$13 x^{2} + 31 x + 10 (Given)$
$= 13 x^{2} + 26 x + 5 x + 10$
$= (x + 2) (13 x + 5)$
$∴ 13 x^{2} + 31 x + 10 = (x + 2) (13 x + 5)$

Suggest Corrections

Similar questions

x^{3} + 13 x^{2} + 31 x - 45

It is given that (x-1) is a factor of the

polynomial f (x) = x^{3} + 13 x^{2} + 31 x - k .

The value of k is:

21 x^{2} - 31 x + 8

x^{3} + 12 x^{2} - 31 x - 42

Join BYJU'S Learning Program