Factorise:
$14 x^{2} + x - 3$

(2 x + 1) (7 x + 3)

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(2 x + 1) (7 x - 3)

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(7 x + 1) (2 x - 3)

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(7 x + 1) (2 x + 3)

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Solution

The correct option is A $(2 x + 1) (7 x - 3)$
$F a c t o r i z i n g 14 x^{2} + x - 3, S p l i t x a s : = 14 x^{2} + 7 x - 6 x - 3 = 7 x (2 x + 1) - 3 (2 x + 1) = (7 x - 3) (2 x + 1)$

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