Factorise : $15 (x - 2 y)^{2} - 8 (x - 2 y) - 16$

(5 x + 10 y - 9) (3 x + 2 y - 4)

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(9 x - 4 y) (x - 2 y)

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(5 x - 10 y + 4) (3 x - 6 y - 4)

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(9 x - 4 y + 3) (3 x - 2 y + 4)

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Solution

The correct option is C $(5 x - 10 y + 4) (3 x - 6 y - 4)$
$15 (x - 2 y)^{2} - 8 (x - 2 y) - 16$
let x-2y=p then,
$15 (x - 2 y)^{2} - 8 (x - 2 y) - 16 = 15 p^{2} - 8 p - 16$
$= 15 p^{2} + 12 p - 20 p - 16$
$= 3 p (5 p + 4) - 4 (5 p + 4)$
$= (5 p + 4) (3 p - 4)$
Substituting p=x-2y we get
$= [5 (x - 2 y) + 4] [3 (x - 2 y) - 4]$
$= (5 x - 10 y + 4) (3 x - 6 y - 4)$

Suggest Corrections

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