Question

Factorise:
16(2p − 3q)² − 4(2p − 3q)

Answer 1

We have:
$$\begin{gathered} 16{\left(2p-3q\right)}^2-4\left(2p-3q\right)=\left(2p-3q\right)\left\{16\left(2p-3q\right)-4\right\} \\ =\left(2p-3q\right)\left(32p-48q-4\right) \end{gathered}$$

∴ $16{\left(2p-3q\right)}^2-4\left(2p-3q\right)=\left(2p-3q\right)\left(32p-48q-4\right)$