Factorise $169 a^{4} - 121 b^{2}$ .

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Solution

As we know the algebraic identity,
$a^{2} - b^{2} = (a - b) (a + b)$
So, it can be factorized by using this identity, we can write:
$169 a^{4} - 121 b^{2}$ $=$ ${(13 a^{2})}^{2} - {(11 b)}^{2}$
$=$ $(13 a^{2} + 11 b) (13 a^{2} - 11 b)$
Therefore factors of $169 a^{4} - 121 b^{2}$ = $(13 a^{2} + 11 b) (13 a^{2} - 11 b)$ .

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