Using a^2 b^2=(a+b)(a b) 16a^2 144=(4a)^2=(12)^2 =(4a+12)(4a 12) =4(a+3)× 4(a 3) =16(a+3)(a 3) ...

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Factorisation Using Algebraic Identities

Factorise : 1...

Question

Factorise :

$16 a^{2} - 144$

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Solution

Using $a^{2} - b^{2} = (a + b) (a - b) 16 a^{2} - 144 = (4 a)^{2} = (12)^{2} = (4 a + 12) (4 a - 12) = 4 (a + 3) \times 4 (a - 3) = 16 (a + 3) (a - 3)$

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