nbsp;We have: nbsp; nbsp; nbsp; nbsp; nbsp;16a2 144=4a2 122 #160; #160; #160; #160; #160; #160; #160; #160; #160; #160; ...

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Factorisation by Common Factors

Factorise:16 ...

Question

Factorise:
16a² − 144

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Solution

We have:
$16 a^{2} - 144 = {(4 a)}^{2} - {(12)}^{2} = (4 a + 12) (4 a - 12) = 4 (a + 3) 4 (a - 3) = 16 (a + 3) (a - 3)$

∴ $16 a^{2} - 144 = 16 (a + 3) (a - 3)$

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