Factorise - 16x-2-8xy-y-2-4x-y-2-8x-y-2-4x-2y-2-4x-y-

The correct option is A (4x+y)^216x^2+8xy+y^2 =(4x)^2+2×(4x)×y+(y)^2 Comparing this with the identity: nbsp; a^2+2ab+b^2= (a+b)^2 (4x)^2+2×(4x)×y+(y)^2=(4x+y ...

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Byju's Answer

Standard VII

Mathematics

(a + b)^2 = a^2 + 2ab +b^2

Factorise : 1...

Question

$F a c t o r i s e : 16 x^{2} + 8 x y + y^{2}$

(4 x + y)^{2}

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(8 x + y)^{2}

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(4 x + 2 y)^{2}

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(4 x + y)

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Solution

The correct option is A $(4 x + y)^{2}$
$16 x^{2} + 8 x y + y^{2} = (4 x)^{2} + 2 \times (4 x) \times y + (y)^{2}$
Comparing this with the identity:
$a^{2} + 2 a b + b^{2} = (a + b)^{2} (4 x)^{2} + 2 \times (4 x) \times y + (y)^{2} = (4 x + y)^{2}$

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Similar questions

Q. Find the vertex, focus, axis, directrix and latus-rectum of the following parabolas
(i) y² = 8x
(ii) 4x² + y = 0
(iii) y² − 4y − 3x + 1 = 0
(iv) y² − 4y + 4x = 0
(v) y² + 4x + 4y − 3 = 0
(vi) y² = 8x + 8y
(vii) 4 (y − 1)² = − 7 (x − 3)
(viii) y² = 5x − 4y − 9
(ix) x² + y = 6x − 14

Factorize:

$4 (x - y)^{2} + 12 (x - y) (x + y) + 9 (x + y)^{2}$

Q. Factorise

{(4 x + y)}^{2} + (4 x + y) (x + 2 y) - 20 {(x + 2 y)}^{2}

F a c t o r i s e : 16 x^{2} + 8 x y + y^{2}

Q. Factorise:

4 (x - y)^{2} - 12 (x - y) (x + y) + 9 (x + y)^{2}

.........[3 marks]

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Factorise:16x2+8xy+y2

The correct option is A (4x+y)216x2+8xy+y2=(4x)2+2×(4x)×y+(y)2 Comparing this with the identity: a2+2ab+b2=(a+b)2(4x)2+2×(4x)×y+(y)2=(4x+y)2

$F a c t o r i s e : 16 x^{2} + 8 x y + y^{2}$

The correct option is A $(4 x + y)^{2}$
$16 x^{2} + 8 x y + y^{2} = (4 x)^{2} + 2 \times (4 x) \times y + (y)^{2}$
Comparing this with the identity:
$a^{2} + 2 a b + b^{2} = (a + b)^{2} (4 x)^{2} + 2 \times (4 x) \times y + (y)^{2} = (4 x + y)^{2}$