Factorise:
$16 x^{5} - 144 x^{3}$

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Solution

We have, $16 x^{5} - 144 x^{3}$
$= 16 x^{3} (x^{2} - 9)$ [Taking $16 x^{3}$ common ]
$= 16 x^{3} (x^{2} - 3^{2})$
$= 16 x^{3} (x - 3) (x + 3)$ [Using the identity $(a^{2} - b^{2}) = (a - b) (a + b)$ ]

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