1
Question
Factorise:
(17) 81a2 – 72ab + 16b2
(17) 81a2 – 72ab + 16b2
Open in App
Solution
81a2 – 72ab + 16b2
= (9a)2 – 2 × 9a × 4b + (4b)2
= (9a – 4b)2 [a2 – 2ab + b2 = (a – b)2]
= (9a – 4b) (9a – 4b)
∴ 81a2 – 72ab + 16b2 = (9a – 4b) (9a – 4b)
= (9a)2 – 2 × 9a × 4b + (4b)2
= (9a – 4b)2 [a2 – 2ab + b2 = (a – b)2]
= (9a – 4b) (9a – 4b)
∴ 81a2 – 72ab + 16b2 = (9a – 4b) (9a – 4b)
Suggest Corrections
1
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
