Question

Factorise:

(18) 4p² + 24pq + 36q²

Answer 1

4p² + 24pq + 36q²
= 4 ( p² + 6pq + 9q² )
= 4 { (p)² + 2 × p × 3q + (3q)² }
= 4 (p + 3q)² [a² + 2ab + b² = (a + b)²]
= 4 (p + 3q) (p + 3q)
∴ 4p² + 24pq + 36q² = 4 (p + 3q) (p + 3q)