2
Question
Factorise:
(18) 4p2 + 24pq + 36q2
(18) 4p2 + 24pq + 36q2
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Solution
4p2 + 24pq + 36q2
= 4 ( p2 + 6pq + 9q2 )
= 4 { (p)2 + 2 × p × 3q + (3q)2 }
= 4 (p + 3q)2 [a2 + 2ab + b2 = (a + b)2]
= 4 (p + 3q) (p + 3q)
∴ 4p2 + 24pq + 36q2 = 4 (p + 3q) (p + 3q)
= 4 ( p2 + 6pq + 9q2 )
= 4 { (p)2 + 2 × p × 3q + (3q)2 }
= 4 (p + 3q)2 [a2 + 2ab + b2 = (a + b)2]
= 4 (p + 3q) (p + 3q)
∴ 4p2 + 24pq + 36q2 = 4 (p + 3q) (p + 3q)
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