1
Question
Factorise:
(2) 1 − 8a + 16a2
(2) 1 − 8a + 16a2
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Solution
1 − 8a + 16a2
= (1)2 − 2 × 1 × 4a + (4a)2
= (1 − 4a)2 [a2 − 2ab + b2 = (a − b)2]
= (1 − 4a) (1 − 4a)
∴ 1 − 8a + 16a2 = (1 − 4a) (1 − 4a)
= (1)2 − 2 × 1 × 4a + (4a)2
= (1 − 4a)2 [a2 − 2ab + b2 = (a − b)2]
= (1 − 4a) (1 − 4a)
∴ 1 − 8a + 16a2 = (1 − 4a) (1 − 4a)
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