1
Question
Factorise: (p2−2pq+q2)−r2 (3 marks)
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Solution
(p2−2pq+q2)−r2
We know that,
(a−b)2=a2−2ab+b2a2−b2=(a+b)(a−b) (1 mark)
⇒(p2−2pq+q2)−r2=(p−q)2−r2=(p−q−r)(p−q+r)
(2 marks)
We know that,
(a−b)2=a2−2ab+b2a2−b2=(a+b)(a−b) (1 mark)
⇒(p2−2pq+q2)−r2=(p−q)2−r2=(p−q−r)(p−q+r)
(2 marks)
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