Factorise :
$2 (x^{2} - 6 x)^{2} - 8 (x^{2} - 6 x + 3) - 40$

2 (x^{2} + 6 x - 4) (x^{2} - 6 x)

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2 (x^{2} + 7 x + 3) (x^{2} - 6 x - 8)

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2 (x^{2} + x + 4) (x^{2} - 6 x)

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2 (x^{2} - 6 x + 4) (x^{2} - 6 x - 8)

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Solution

The correct option is C $2 (x^{2} - 6 x + 4) (x^{2} - 6 x - 8)$
$2 (x^{2} - 6 x)^{2} - 8 (x^{2} - 6 x + 3) - 40$
Let $x^{2} - 6 x = a$
$=> 2 a^{2} - 8 (a + 3) - 40$
$=> 2 a^{2} - 8 a - 24 - 40$
$=> 2 a^{2} - 8 a - 64$
$=> 2 (a^{2} - 4 a - 32)$
$=> 2 (a^{2} - 8 a + 4 a - 32)$
$=> 2 [a (a - 8) + 4 (a - 8)]$
$=> 2 (a - 8) (a + 4)$
Putting the value of $a$
$=> 2 (x^{2} - 6 x - 8) (x^{2} - 6 x + 4)$

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