Factorise :

$20 a^{2} - 45 b^{2}$

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Solution

$20 a^{2} - 45 b^{2} = 5 {4 a^{2} - 9 b^{2}} = 5 {(2 a)^{2} - (3 b)^{2}} = 5 (2 a + 3 b) (2 a + 3 b) A n s .$

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