Question

Factorise:

$24l^2-\frac{6}{25}{m}^2$.

Answer 1

$6[4l^2-{\frac{m}{25}}^2]$=>$6[(2l{)}^2-(\frac{m}{5}{)}^2$=>$6[2l-\frac{m}{5})(2l+\frac{m}{5})]$

$[\because a^2-b^2=(a-b\left)\right(a+b\left)\right]$