Factorise: $24 x^{2} - 6 x y - 9 y^{2}$

3 (2 x + y) (4 x - 3 y)

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(2 x + 5) (7 x + 6)

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(2 x - y) (2 x - 3 y)

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None of these

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Solution

The correct option is A $3 (2 x + y) (4 x - 3 y)$
$24 x^{2} - 6 x y - 9 y^{2}$
$\Rightarrow 3 (8 x^{2} - 2 x y - 3 y^{2})$
$= 3 [8 x^{2} + 4 x y - 6 x y - 3 y^{2}]$
$= 3 [4 x (2 x + y) - 3 y (2 x + y)]$
$= 3 (2 x + y) (4 x - 3 y)$

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Similar questions

Factorise Completely : $x^{2} + 6 x y + 9 y^{2} + x + 3 y$

4 x^{2} - 9 y^{2} - 2 x - 3 y

Find the product of $(2 x - 3 y)$ and $(4 x^{2} + 9 y^{2} + 6 x y)$ .

(2 x - 3 y + 5 z)

(4 x^{2} + 9 y^{2} + 25 z^{2} + 6 x y + 15 y z - 10 x z)

\frac{2 x}{3 y} = \frac{3 y}{4 z}

4 x^{2} + 9 y^{2} + 16 z^{2} = (2 x - 3 y + 4 z) (2 x + 3 y + 4 z)

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