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Question

Factorise : 250x3432y3

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Solution

We know that,
a3b3=(ab)(a2+b2+ab)

Now,
250x3432y3=2(125x3216y3)

=2{(5x)3(6y)3}

=2(5x6y)(25x2+36y2+5x×6y)

=2(5x6y)(25x2+36y2+30xy)


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