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Polynomials

Factorise:25 ...

Question

Factorise:

25a^2-35a+12

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Solution

Factor 25a^2−35a+12
25a^2−20a-15a+12
=5a(5a-4)-3(5a-4)
=(5a-4)(5a-3)

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Q. Find the roots of the equation: :

25 a^{2} - 35 a + 12

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2 {(a - 2 b)}^{2} - 25 (a - 2 b) + 12

Q. Give possible expression for the length and breadth of the rectangle whose area is :

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$25 x^{2} - 4$ can be factorised as:

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