Factorise:
25x²– 10x + 1 – 36y²

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Solution

$25 x^{2} - 10 x + 1 - 36 y^{2} = [{(5 x)}^{2} - 2 \times 5 x \times 1 + 1^{2}] - {(6 y)}^{2} = {(5 x - 1)}^{2} - {(6 y)}^{2} [a^{2} - 2 a b + b^{2} = {(a - b)}^{2}] = [(5 x - 1 + 6 y)] [(5 x - 1 - 6 y)] [a^{2} - b^{2} = (a + b) (a - b)] = (5 x + 6 y - 1) (5 x - 6 y - 1)$

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Factorise:
$25 x^{2} - 10 x + 1 - 36 y^{2}$

Factorize the following algebraic expression: $25 x^{2} - 10 x + 1 - 36 y^{2}$

25 x^{2} + 36 y^{2} + 49 z^{2} + 60 x y - 84 y z - 70 z x

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