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Expression Formation

Factorise 2...

Question

Factorise $27 a^{3} + 64 b^{3}$

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Solution

Factorize:-

$27 a^{3} + 64 b^{3}$

$= {(3 a)}^{3} + {(4 b)}^{3}$

$= (3 a + 4 b) [{(3 a)}^{2} + {(4 b)}^{2} - 2 \times 3 a \times 4 b]$

$= (3 a + 4 b) (9 a^{2} + 16 b^{2} - 24 a b)$
Hence, this is the answer.

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