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Question

Factorise:
27a275b2.

A
(3a+5b)(3a5b)
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B
3(3a+5b)(3a+5b)
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C
(3a+5b)(ab)
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D
3(3a+5b)(3a5b)
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Solution

The correct option is D 3(3a+5b)(3a5b)
27a275b2
=3(9a225b2)
=3[(3a)2(5b)2]
=3(3a+5b)(3a5b) (Using a2b2=(a+b)(ab))

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