Factorise: $27 x^{3} - 1$ .

(3 x - 1) (9 x^{2} + 3 x + 1)

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(3 x + 1) (9 x^{2} + 3 x + 1)

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(3 x - 1) (9 x^{2} - 3 x + 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(3 x + 1) (9 x^{2} - 3 x + 1)

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Solution

The correct option is A $(3 x - 1) (9 x^{2} + 3 x + 1)$
Using the identity:
$a^{3} - b^{3} = (a - b) (a^{2} + b^{2} + a b)$
$27 x^{3} - 1 = (3 x)^{3} - 1^{3} = (3 x - 1) (9 x^{2} + 1 + 3 x)$

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Similar questions

3 x + \frac{1}{3 x} = 3

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If $3 x + \frac{1}{3 x} = 3; f i n d : (i) 9 x^{2} + \frac{1}{9 x^{2}} (i i) 27 x^{3} + \frac{1}{27 x^{3}}$

3 x + \frac{1}{3 x} = 3

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x \neq 0

3 x + \frac{1}{3 x} = 8

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