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Question

Factorise : 2a+6b3(a+3b)2
2a+6b3(a+3b)2
=2(a+3b)3(a+3b)2 [Taking 2 common from 2a+6b]
=(a+3b){23(a+3b)} [Taking (a+3b) common]
=(a+3b)(23a9b)

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Solution

\N

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