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Byju's Answer
Standard VIII
Mathematics
Method of Common Factors
Factorise : 2...
Question
Factorise :
2
a
+
6
b
−
3
(
a
+
3
b
)
2
2
a
+
6
b
−
3
(
a
+
3
b
)
2
=
2
(
a
+
3
b
)
−
3
(
a
+
3
b
)
2
[
T
a
k
i
n
g
2
c
o
m
m
o
n
f
r
o
m
2
a
+
6
b
]
=
(
a
+
3
b
)
{
2
−
3
(
a
+
3
b
)
}
[
T
a
k
i
n
g
(
a
+
3
b
)
c
o
m
m
o
n
]
=
(
a
+
3
b
)
(
2
−
3
a
−
9
b
)
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Solution
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3
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Q.
Factorise:
2a + 6b − 3(a + 3b)
2
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Evaluate:
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2a+6b-3(a+3b)^2
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∣
∣ ∣
∣
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Q.
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