CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Method of Common Factors

Factorise : 2...

Question

Factorise : $2 a + 6 b - 3 (a + 3 b)^{2}$
$2 a + 6 b - 3 (a + 3 b)^{2}$
$= 2 (a + 3 b) - 3 (a + 3 b)^{2} [T a k i n g 2 c o m m o n f r o m 2 a + 6 b]$
$= (a + 3 b) {\begin{matrix} 2 - 3 (a + 3 b) \end{matrix}} [T a k i n g (a + 3 b) c o m m o n]$
$= (a + 3 b) (2 - 3 a - 9 b)$

Open in App

Solution

\N

Suggest Corrections

thumbs-up

2

Similar questions

Q. Factorise:
2a + 6b − 3(a + 3b)²

2 a + 6 b - 3 (a + 3 b)^{2}

Q. 2a+6b-3(a+3b)^2

∣ ∣ ∣ ∣ \begin{matrix} a & a + b & a + b + c 2 a & 3 a + 2 b & 4 a + 3 b + 2 c 3 a & 6 a + 3 b & 10 a + 6 b + 3 a \end{matrix} ∣ ∣ ∣ ∣ = a^{3}

3 a - 4 b + 4 c, 2 a + 3 b - 8 c, a - 6 b + c

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Methods of Factorisation

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Method of Common Factors

Standard VIII Mathematics

Join BYJU'S Learning Program

CrossIcon