Byju's Answer
Standard VIII
Mathematics
Method of Common Factors
Factorise : 2...
Question
Factorise :
2
a
+
6
b
−
3
(
a
+
3
b
)
2
2
a
+
6
b
−
3
(
a
+
3
b
)
2
=
2
(
a
+
3
b
)
−
3
(
a
+
3
b
)
2
[
T
a
k
i
n
g
2
c
o
m
m
o
n
f
r
o
m
2
a
+
6
b
]
=
(
a
+
3
b
)
{
2
−
3
(
a
+
3
b
)
}
[
T
a
k
i
n
g
(
a
+
3
b
)
c
o
m
m
o
n
]
=
(
a
+
3
b
)
(
2
−
3
a
−
9
b
)
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Solution
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Similar questions
Q.
Factorise:
2a + 6b − 3(a + 3b)
2
Q.
Evaluate:
2
a
+
6
b
−
3
(
a
+
3
b
)
2
Q.
2a+6b-3(a+3b)^2
Q.
∣
∣ ∣
∣
a
a
+
b
a
+
b
+
c
2
a
3
a
+
2
b
4
a
+
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b
+
2
c
3
a
6
a
+
3
b
10
a
+
6
b
+
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a
∣
∣ ∣
∣
=
a
3
Q.
Add:
3
a
−
4
b
+
4
c
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2
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8
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