Factorise 2a7−128a
2a(a+2)(a−2)(a2−2a+4)(a2+2a+4)
(a+2)(a−2)(a2−2a+4)(a2+2a+4)
2a(a+2)(a−2)(a2−2a+4)
2a(a+2)(a2−2a+4)(a2+2a+4)
2a7−128a = 2a(a6−64)
= 2a[(a3)2−(8)2]
= 2a(a3+8)(a3−8)
= 2a(a3+23)(a3−23)
= 2a(a+2)(a2−2a+4)(a−2)(a2+2a+4) = 2a(a+2)(a−2)(a2−2a+4)(a2+2a+4)