Factorise $2 a b^{2} - a b y + 2 c b y - c y^{2}$

(2 b - y) (a b - c y)

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(2 b + y) (a b - c y)

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(b - y) (a b - c y)

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(2 b - y) (a b + c y)

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Solution

The correct option is D $(2 b - y) (a b + c y)$
$F a c t o r i z i n g {2 a b}^{2} - a b y + 2 c b y - c y^{2}, = a b (2 b - y) + c y (2 b - y) = (2 b - y) (a b + c y)$

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Similar questions

Factorise : $2 a b^{2} - a b y + 2 c b y - c y^{2}$

(x - y)^{2} a^{2} + 2 (x - y) (x + y) a b + b^{2} (x + y)^{2}

Given:

$a = (x + y)$

$b = (x - y)$

$a b = x^{p} - y^{q}$

Then, p+q=___.

x^{a} \times y^{a} =

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