Factorise: 2ax+2bx−ay−by
(a + b) (x - y)
Consider the expression,
2ax+2bx−ay−by....(i)
Taking 2x common from first two terms and −y common from last two terms of expression (i), we get
=2x(a+b)−y(a+b)...(ii)
Taking (a+b) common from expression (ii), we get
(a+b)(2x−y)
⇒ 2ax+2bx−ay−by=(a+b)(2x−y)
Therefore, the factors of 2ax+2bx−ay−by are (a+b) and (2x−y).