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Question

Factorise:
2b(2a+b)−3c(2a+b)

A
(2a+b)(2b+3c)
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B
(2ab)(2b3c)
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C
(a+b)(2b3c)
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D
(2a+b)(2b3c)
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Solution

The correct option is D (2a+b)(2b3c)
Factorizing2b(2a+b)3c(2a+b),wetake(2a+b)common,=(2a+b)(2b3c)

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