Factorise: $2 p (x + y) - 3 q (x + y)$

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Solution

Since in the expression $2 p (x + y) - 3 q (x + y)$ , $(x + y)$ is the common term, therefore, can be factorised as follows:

$2 p (x + y) - 3 q (x + y) = (x + y) (2 p - 3 q)$

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Factorise:
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