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Question

Factorise : 2x224x+72

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Solution

Given: 2x224x+72
=2(x212x+36), (take 2 common)
=2(x26x6x+36), (split middle term)
=2[(x26x)+(6x+36)],( group pair of terms)
=2[x(x6)6(x6)], (factor each binomials)
=2(x6)(x6)
=2(x6)2

Aliter, use (ab)2=a22ab+b2
2(x212x+36)=2(x22×6x+62)=2(x6)2


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