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Question

Factorise:
2x2+33x+3


Solution

We have to split 3root3 into two numbers such that their sum is 3root3 and their product is 6, i.e.,2×3.

Clearly, 23+3=33 and 23×3=6.

2x2+33x+3=2x2+23x+3x+3=2x(x+3)+3(x+3)=(x+3)(2x+3)


Mathematics
Secondary School Mathematics IX
Standard IX

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