Factorise:
$2 x^{2} - x + \frac{1}{8}$

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Solution

$2 x^{2} - x + \frac{1}{8} = 2 x^{2} - \frac{1}{2} x - \frac{1}{2} x + \frac{1}{8} = 2 x (x - \frac{1}{4}) - \frac{1}{2} (x - \frac{1}{4}) = (x - \frac{1}{4}) (2 x - \frac{1}{2})$

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Similar questions

2 x^{2} - x - 3

- 2 x^{2} + 3 x + 9

2 x^{2} - x + \frac{1}{8} = 0

Factorise : [4 MARKS]
$1) x^{3} - 2 x^{2} - x + 2$
$2) 2 y^{3} + y^{2} - 2 y - 1$

Factorise :
(i) $x^{3}$ −2 $x^{2}$ −x+2
(ii) 2 $y^{3}$ + $y^{2}$ −2y−1

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