Factorise $2 x^{3} b^{2} - 4 x^{5} b^{4}$

2 x^{3} b^{2} (1 + 2 x^{2} b^{2})

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2 x^{3} b^{2} (1 - 2 x^{2} b^{2})

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2 x^{3} b^{2} (1 - x^{2} b^{2})

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x^{3} b^{2} (1 - 2 x^{2} b^{2})

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Solution

The correct option is A $2 x^{3} b^{2} (1 - 2 x^{2} b^{2})$
$F a c t o r i z i n g 2 x^{3} b^{2} - 4 x^{5} b^{4}, w e t a k e 2 x^{3} b^{2} c o m m o n, = 2 x^{3} b^{2} (1 - 2 x^{2} b^{2})$

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