The given equation can be written as 2x2+5x+4x+10
By taking the common factor outside the bracket, we get x(2x+5)+2(2x+5) here (2x+5) is common that is taken outside
Factorising we get, (2x+5)(x+2)
Factorise 2(x+y)^2 - 9 (x+y) - 5