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Byju's Answer
Standard VIII
Mathematics
Factorisation by Regrouping Terms
Factorise : ...
Question
Factorise :
3
a
c
+
7
b
c
−
3
a
d
−
7
b
d
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Solution
GIven that:
3
a
c
+
7
b
c
−
3
a
d
−
7
b
d
=
(
3
a
c
+
7
b
c
)
+
(
−
3
a
d
−
7
b
d
)
, (group pair of terms)
=
c
(
3
a
+
7
b
)
−
d
(
3
a
+
7
b
)
, (factor each binomials)
=
(
3
a
+
7
b
)
(
c
−
d
)
, (factor out common factor
(
3
a
+
7
b
)
)
The factors of
3
a
c
+
7
b
c
−
3
a
d
−
7
b
d
are
(
3
a
+
7
b
)
(
c
−
d
)
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Q.
Factorise:
(i)
; (ii)
; (iii)
;
(iv)