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Question

Factorise : 3ac+7bc3ad7bd

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Solution

GIven that: 3ac+7bc3ad7bd
=(3ac+7bc)+(3ad7bd), (group pair of terms)
=c(3a+7b)d(3a+7b), (factor each binomials)
=(3a+7b)(cd), (factor out common factor (3a+7b))
The factors of 3ac+7bc3ad7bd are (3a+7b)(cd)

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