Factorise: $3 a x - 6 a y - 8 b y + 4 b x$

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Solution

We need to factorise $3 a x - 6 a y - 8 b y + 4 b x$
It can be written as $3 a x - 6 a y - 8 b y + 4 b x = 3 a (x - 2 y) + 4 b (x - 2 y)$
Thus factors are $(x - 2 y) (3 a + 4 b)$ .

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Similar questions

3 a x - 6 x y + 8 b y - 4 b x

3 a x - 6 x y + 8 b y - 4 a b

c > 0

3 a x^{2} + 4 b x + c = 0

x^{2} - x y + 2 y^{2} - 2 a x - 6 a y + 7 a^{2} = 0 .

f (x) = 3 a x^{2} - 4 b x + c (a, b, c \in R, a \neq 0)

a, b, c

A . P

f (x) = 0

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