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Question
Factorise 3u³-4u²-12u+16
Factorise 3u³-4u²-12u+16
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Solution
3u^3 - 4u2-12 u + 16
=(3u^3 -4u^2) - (12u- 16)
= u^2 (3u- 4) - 4( 3u-4)
= ( u^2 -4)(3u-4)
= ( u-2 )(u +2)(3u - 4)
Thank you :)
=(3u^3 -4u^2) - (12u- 16)
= u^2 (3u- 4) - 4( 3u-4)
= ( u^2 -4)(3u-4)
= ( u-2 )(u +2)(3u - 4)
Thank you :)
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