Factorise :

$(3 x - 4 y)^{2} - 25 z^{2}$

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Solution

$(3 x - 4 y)^{2} - 25 z^{2} = (3 x - 4 y)^{2} - (5 z)^{2} = (3 x - 4 y + 5 z) (3 x - 4 y - 5 z) A n s .$

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Similar questions

Q. Factorise the following expressions :

9 (3 x - 4 y)^{2} - 12 (4 y - 3 x)

Factorise:
$4 x^{2} + 9 y^{2} + 25 z^{2} + 12 x y + 30 y z + 20 z x$

Find the following products:

(i) (3x + 2y + 2z) (9x² + 4y² + 4z² − 6xy − 4yz − 6zx)

(ii) (4x − 3y + 2z) (16x² + 9y² + 4z² + 12xy + 6yz − 8zx)

(iii) (2ab − 3b − 2c) (4a² + 9b² +4c² + 6 ab − 6 bc + 4ca)

(iv) (3x − 4y + 5z) (9x² +16y²+ 25z² + 12xy −15zx + 20yz)

Q. Factorise the following trinomials:

\frac{x^{2}}{4 y^{2}} - \frac{2}{3} + \frac{4 y^{2}}{9 x^{2}}

Q. Factorise:

{(x + 4 y)}^{2} - 4 z^{2}

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Factorise : (3x−4y)2−25z2

(3x−4y)2−25z2=(3x−4y)2−(5z)2=(3x−4y+5z)(3x−4y−5z) Ans.

Factorise :

$(3 x - 4 y)^{2} - 25 z^{2}$

$(3 x - 4 y)^{2} - 25 z^{2} = (3 x - 4 y)^{2} - (5 z)^{2} = (3 x - 4 y + 5 z) (3 x - 4 y - 5 z) A n s .$