Factorise $3 x^{5} - 6 x^{4} - 2 x^{3} + 4 x^{2} + x - 2$

(x - 2) (3 x^{4} - 2 x^{2} - 1)

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(x - 2) (x^{4} - 2 x^{2} - 1)

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(x - 2) (3 x^{4} - 2 x^{2} + 1)

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(x - 2) (x^{4} - 2 x^{2} + 1)

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Solution

The correct option is C $(x - 2) (3 x^{4} - 2 x^{2} + 1)$
$F a c t o r i z i n g {3 x}^{5} - {6 x}^{4} {- 2 x}^{3} + 4 x^{2} + x - 2, = {3 x}^{4} (x - 2) - 2 x^{2} (x - 2) + 1 (x - 2) = (x - 2) ({3 x}^{4} - 2 x^{2} + 1)$

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