Factorise : $3 x^{5} - 6 x^{4} - 2 x^{3} + 4 x^{2} + x - 2$

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Solution

$3 x^{5} - 6 x^{4} - 2 x^{3} + 4 x^{2} + x - 2 = 3 x^{4} (x - 2) - 2 x^{2} (x - 2) + 1 (x - 2) = (x - 2) (3 x^{4} - 2 x^{2} + 1)$

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Similar questions

x^{3}

7 x^{5} + 6 x^{4} + \frac{1}{2} x^{3} + \frac{1}{4} x^{2} + x + 2

x^{0}

7 x^{5} + 6 x^{4} + \frac{1}{2} x^{3} + \frac{1}{4} x^{2} + x + 2

f (x) = 2 + 4 x^{2} + 6 x^{4} + 8 x^{6}

Factorise :

$3 x^{5} - 48 x$

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